Question

if cosø+secø=2, show that , cos³ø+sec³ø=2​

Answer 1

Answer:

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Answer 2

Answer:

x², θ ➙

cosø+secø=2

➙ cosø+(1/Cosø) =2

➙ cos²ø - 2cosø + 1 = 0

➙ (cosø - 1) ² = 0

➙ cosø = 1

➙ Secø = 1

So

cos³ø+sec³ø

= (1)³+ (1)³

= 1+1

= 2

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