if cosQ= 3/5, find the value of (5cosecQ_4 tanQ/secQt cotQ)
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cosФ =3/5=b/h so p=4 by using pythagorous theorem
so
5cosecФ- 4(tanФ/secФ cotФ)=5×5/4 - 4(4/3)/(5/3×3/4)
=25/4 -16/3
=11/12
so
5cosecФ- 4(tanФ/secФ cotФ)=5×5/4 - 4(4/3)/(5/3×3/4)
=25/4 -16/3
=11/12
shab:
thanks
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