Math, asked by starlogo25403, 1 year ago

if cosq + cos^2q =1 find the value of (sin^2q + sin^4q)

Answers

Answered by Anonymous
5
Given :

cosQ + cos²Q = 1

cosQ = 1 - cos²Q

{ Using identity -

cos²A + sin²A = 1

•°• sin²A = 1 - cos²A }

So,

cosQ = sin²Q _____ ( 1 )

Squaring both sides, we get

( cosQ )² = ( sin²Q )²

cos²Q = sin⁴Q _______ ( 2 )

Now,

cosQ + cos²Q = 1 ( Given )

sin²Q + sin²Q = 1 [ From ( 1 ) and ( 2 ) ]

Hence, proved.
Answered by Anonymous
1

Answer is  Sin^2q + Sin^4q =1

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