if cosq + cos^2q =1 find the value of (sin^2q + sin^4q)
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Answered by
5
Given :
cosQ + cos²Q = 1
cosQ = 1 - cos²Q
{ Using identity -
cos²A + sin²A = 1
•°• sin²A = 1 - cos²A }
So,
cosQ = sin²Q _____ ( 1 )
Squaring both sides, we get
( cosQ )² = ( sin²Q )²
cos²Q = sin⁴Q _______ ( 2 )
Now,
cosQ + cos²Q = 1 ( Given )
sin²Q + sin²Q = 1 [ From ( 1 ) and ( 2 ) ]
Hence, proved.
cosQ + cos²Q = 1
cosQ = 1 - cos²Q
{ Using identity -
cos²A + sin²A = 1
•°• sin²A = 1 - cos²A }
So,
cosQ = sin²Q _____ ( 1 )
Squaring both sides, we get
( cosQ )² = ( sin²Q )²
cos²Q = sin⁴Q _______ ( 2 )
Now,
cosQ + cos²Q = 1 ( Given )
sin²Q + sin²Q = 1 [ From ( 1 ) and ( 2 ) ]
Hence, proved.
Answered by
1
Answer is Sin^2q + Sin^4q =1
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