Question

if
CosQ= I/√2, where Q is an acute angle then find the value of sinQ and cosQ​

Answer 1

Step-by-step explanation:

Given,

$cosQ = \frac{1}{ \sqrt{2} } \\ = > cosQ = cos45 \\ = > Q = 45$

Therefore,

$sinQ = sin45 = \frac{1}{ \sqrt{2} }$

You have already written the value of cosQ

Answer 2

Answer:

1/√2

Step-by-step explanation:

cos Q = 1/√2

cos Q = 1/√2 = 45°

Q = 45°

sin Q = sin 45° = 1/√2

cos Q = cos 45° = 1/√2

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