Question

. If cost of 6 kg apples and 5 kg grapes is Rs 750 while 3 kg apples and 2 kg grapes

is Rs 430 . Form linear equations to represent this situation
​

Answer 1

Step-by-step explanation:

let's 6 kg apples equals to 6x

then 5 kg grapes equals to 5x

6 X + 5 X equal to 750

11 X equals to 750

X equals to 750 by 11

X = 68.181

now second equation

3 kg apples equals to 3 x and 2 kg grapes equals to 2x

3 x + 2 X equals to 430

5x equals to 430

X equals to 430 by 5

X equals to 86

so the cost of apples is 3 into 86 equals to 258

cost of

Answer 2

Given:

If cost of 6 kg apples and 5 kg grapes is Rs 750 while 3 kg apples and 2 kg grapes  is Rs 430

To find:

The linear equations for the given condition of the question.

Solution:

Let the rate of Apple per kg is ₹X

And the rate of grapes per Kg is ₹Y

As per the given condition the linear equations are given as:

CASE 1:

Cost of 6 kg apples and 5 kg grapes is Rs 750

Cost of the 6 Kg apples will be 6X

and the Cost of the 5Kg grapes will be 5Y

So the equation will be:

6X + 5Y = 750

CASE 2:

The cost of 3 kg apples and 2 kg grapes  is Rs 430

Cost of the 3 Kg apples will be 3X

and the Cost of the 2 Kg grapes will be 2Y

So the equation will be:

3X + 2Y = 430