if cost of one bag (50 kg) of urea is Rs. 276. the price per kg of nitrogen will be .
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Solution:-
we know that,
The formula for urea is (NH2)2CO.
The molar mass for urea is 14*2+1*4+12+16= 60 g/mole.
In this 60g of urea, nitrogen has a mas of 28 g.
So by simple proportion in 50 kg of urea, nitrogen has a mass = 50 kg*28 g/60 g = 23.0 kg.
we have ,
the cost of 50kg urea = 276 Rs.
urea's 1kg cost = 276/50 = 5.52 Rs
per kg price of nitrogen = 276/23.0 = 12 Rs
●hence the price per kg of nitrogen = 12 Rs
■I HOPE ITS HELP■
we know that,
The formula for urea is (NH2)2CO.
The molar mass for urea is 14*2+1*4+12+16= 60 g/mole.
In this 60g of urea, nitrogen has a mas of 28 g.
So by simple proportion in 50 kg of urea, nitrogen has a mass = 50 kg*28 g/60 g = 23.0 kg.
we have ,
the cost of 50kg urea = 276 Rs.
urea's 1kg cost = 276/50 = 5.52 Rs
per kg price of nitrogen = 276/23.0 = 12 Rs
●hence the price per kg of nitrogen = 12 Rs
■I HOPE ITS HELP■
Answered by
3
The formula for urea is (NH2)2CO.
The molar mass for urea is 14*2+1*4+12+16= 60 g/mole. In this 60g of urea, nitrogen has a mas of 28 g. Using the techniquea of simple proportion in 50 kg of urea, nitrogen has a mass = 50 kg*28 g/60 g = 23.0 kg. And we have ,
the cost of 50kg urea = 276 Rs.
urea's 1kg cost = 276/50 = 5.52 Rs
per kg price of nitrogen = 276/23.0 = 12
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