if costheta=2/3 then find the value of 2secsquaretheta+2tansquaretheta-7
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Step-by-step explanation:
Given, Cosθ=2/3
Note, Cosθ=Secθ
and 1+Tan²θ=Sec²θ
Then, 2Sec²θ+2Tan²θ-7=2Sec²θ+2(Sec²θ-1)-7
=4Sec²θ-9=4/Cos²θ -9=4/(4/9) -9=9-9=0
Hence, 2Sec²θ+2Tan²θ=0
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