if costheta=√3/2 . prove that tantheta=1/√3 and cosectheta = 2
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tanθ=3/4
sec²θ =1+tan²θ =1+(3/4)²=1+9/16=25/16
Hence secθ = ±√(25/16)=±5/4
Hence cosθ=1/secθ=±4/5
Since tanθ=sinθ/cosθ
Hence sinθ=tanθ ×cosθ
Hence sinθ=(3/4)×(±4/5)=±3/5
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