Question

if costhita =3/5 then what is the value of 6tanthita-5costhita​

Answer 1

$\bigstar$ Answer :

5 is the answer

$\bigstar$  Step-by-step explanation :

$\star$ Given $cos\theta=\frac{3}{5}$

$\implies \frac{adj.side}{hypotenuse}=\frac{3}{5}$

$\star$ Let third side be opposite side.

=> By using Pythagoras theorem,

$\star$ opp²+adj²=hyp²

=> opp²=5²-3²

=> opp²=25-9

=>opp²=16

=> opp=4

$\star$ So ,

$6tan\theta-5cos\theta\\\\\implies 6.\frac{opp.side}{adj.side}- 5.\frac{adj.side}{hyp.}\\\\ \implies 6.\frac{4}{3}-5.\frac{3}{5}\\\\ \implies 2.4 -3\\\\\implies 8-3\\\\\implies 5$

Answer 2

5

Explanation:

Given,

$\cos(tita) = \frac{3}{5}$

$\frac{adj.side}{hyp} = \frac{3}{5}$

Third side = Opposite side

Pythagoras theorem:

${opp}^{2} + {adj}^{2} = {hyp}^{2}$

${opp}^{2} = {5}^{2} - {3}^{2}$

${opp}^{2} = 25 - 9$

${opp}^{2} = 16$

$opp = 4$

so,

6tan(tita) - 5cos(tita)

$6. \frac{opp}{adj} - 5. \frac{adj}{hyp}$

$6. \frac{4}{3} - 5. \frac{3}{5}$

$2 \times 4 - 3$

$8 - 3$

5