Question

If cosX=12/13, then the value of sinX is:​

Answer 1

Answer:

cos =base/hypotenuse

but cos =12/13

base/hypotenuse=12/13

so by Pythagoras theorem

Ac

$ac {}^{2} = ab {}^{2} + bc {}^{2}$

13

$13 { }^{2} - 12 {}^{2} = ab {}^{2}$