Question

if cosx =3/4 then for nd the value of 8tan^2x+9​

Answer 1

cosx = 3/4

secs = 4/3

sec²x = 16/9

tan²x = sec²x - 1 = 16/9 -1 =7/9

8tan²x + 9 = 56/9 + 9= (56+81)/ 9 =137/9