Question

if Cosx = -3/5 x lies in 2 quadrant then find the value of tanx and

Sinx .​

Answer 1

Answer:

Step-by-step explanation:

Given,

x∈ 2nd quadrant and Cosx = -3/5

Let us assume a right angled triangle ∠B=90°,AC=5,BC=3,AB=?

from pythagoras theorem:

(AC)² =(AB)²+(BC)²

(5)²=(AB)²+(3)²

√25-9=(AB)

AB=4

Sinx=opposite/hypotenuse

sinx=4/5

sinx is positive in 2nd quadrant

Tanx=opposite /adjacent

Tanx=-4/3

tanx is negative in 2nd quadrant.