if cosx=cos40.sin50+sin40.cos50 then find the value of x
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Answered by
123
given Cosx =cos40°.sin50°+sin40°.cos50°
=cos(90°-50°).sin50°+sin(90°-50°).cos50°
=sin50°.sin50°+cos50°.cos50°
=sin^2 50°+ cos^2 50°
=1
Now,cos x = 1
cos x =cos 0°
x=0
=cos(90°-50°).sin50°+sin(90°-50°).cos50°
=sin50°.sin50°+cos50°.cos50°
=sin^2 50°+ cos^2 50°
=1
Now,cos x = 1
cos x =cos 0°
x=0
Answered by
46
Answer:
Step-by-step explanation:
HEY!!
HERE IS YOUR ANSWER
:-
given Cosx =cos40°.sin50°+sin40°.cos50°
=cos(90°-50°).sin50°+sin(90°-50°).cos50°
=sin50°.sin50°+cos50°.cos50°
=sin^2 50°+ cos^2 50°
=1
Now,cos x = 1
cos x =cos 0°
x=0
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