Question

if cosx=cos40.sin50+sin40.cos50 then find the value of x

Answer 1

given Cosx =cos40°.sin50°+sin40°.cos50°
=cos(90°-50°).sin50°+sin(90°-50°).cos50°
=sin50°.sin50°+cos50°.cos50°
=sin^2 50°+ cos^2 50°
=1
Now,cos x = 1
cos x =cos 0°
x=0

Answer 2

Answer:

Step-by-step explanation:

HEY!!

HERE IS YOUR ANSWER  

:-  

given Cosx =cos40°.sin50°+sin40°.cos50°

=cos(90°-50°).sin50°+sin(90°-50°).cos50°

=sin50°.sin50°+cos50°.cos50°

=sin^2 50°+ cos^2 50°

=1

Now,cos x = 1

cos x =cos 0°

x=0

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