If cosx = tany, coty = tanz and cotz = tanx, then sinx =
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Answer:
Sinx = [-1+√5]/2 or [-1-√5]/2
Step-by-step explanation:
cosx = tany ........Eq(1)
tanz = coty .........Eq(2)
cotz = tanx .........Eq(3)
multiply Eq(1) Eq(2) and Eq(3)
cosx * tanz * cotz = tany * coty * tanx
here tanz and cotz get cancelled and tany and coty get cancelled,tan is the reciprocal of cot.
cosx = tanx
cosx = sinx/cosx
cos^2x = sinx
1-sin^2x = sinx
sin^2x + sinx - 1 = 0
it is a quadratic equation in variable sinx
sinx = [- 1 ± √(1²-4*1*-1)]2*1
= [-1±√(1+4)]/2
= [-1±√5]/2
therefore sinx = [-1+√5]/2 or [-1-√5]/2
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