If cot 0 = 1; find the value of :
5 tan2 0 + 2 sin2 0 - 3
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cotΘ=1
cotΘ=cot45
Θ=45 ∘
5tan²Θ+2sin²Θ−3= 5tan²45+2sin²45 −3
= 5(1)² +2(1/√2)²-3
=5 +1-3= 6
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