Question

if cot 0=7/8,then the value of (1+sin0) (1-sin0)/(1+cos0) (1-cos0) is
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Answer 1

Answer:

49/64

Step-by-step explanation:

= > (1 + sin0)(1 - sin0) / (1 + cos0)(1 - cos0)

Using (a + b)(a - b) = a² - b²

= > (1² - sin²0)/(1² - cos²0)

= > (1 - sin²0)/(1 - cos²0)

1 - sin²A = cos²A ; 1 - cos²A = sin²A

= > cos²0 / sin²0

= > cot²0

= > (7/8)²

= > 49/64

Answer 2

Answer:

cot 0=7/8

(1+sin 0)(1-sin0)/(1+cos 0)(1-cos0) [a²-b²=(a+b)(a-b)]

(1-sin²0)/(1-cos² 0)

we know that,

• 1-sin ²0=cos ²0

• 1-cos²0=sin²0

=>cos²0/sin²0=cot²0

=>(7/8)²=49/64