If cotθ = 1/√3 verify that 1-cos2θ / 2-sin2θ = 3/5: .
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Given cot θ=1/root3
θ =cot-11/root 3
θ =60 substitute θ value in the given equation
1-cos2 θ /2-sin2 θ
=1-cos260/2-sin260
We know cos 60=1/2 & sin 60 =root3/2
=1-(1/2)2/2-(root3/2)2
=(1-1/4)/(2-3/4)
=(3/4)/(5/4)
=3/5
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