If cotθ=1/root3 thenθ
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Given,
cotθ=
3
1
⇒cotθ=cot60
o
⇒θ=60
o
∴(
2−sin
2
θ
1−cos
2
θ
)
Putting the value of θ we get,
=
2−sin
2
60
o
1−cos
2
60
o
=
2−(
2
3
)
2
1−(
2
1
)
2
=
2−
4
3
1−
4
1
=
4
8−3
4
4−1
=
4
5
4
3
=
5
3
.
HOPE I THELPS:)
p.s.
refer to jpeg
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