Question

If cot⁻¹x+cot⁻¹y+cot⁻¹z=π/2, then x+y+z=........,Select Proper option from the given options.
(a) xy+yz+zx
(b) xyz
(c) 1/x+1/y+1/z
(d) xy+yz+zx/3

Answer 1

Dear Student:

If cot⁻¹x+cot⁻¹y+cot⁻¹z=π/2, then x+y+z=xyz.

See the attachment.