if cot 2 theta = tan 4 theta where 2 theta and 4 theta are acute angles, find the value of sin 3 theta
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Cot2theta=tan4theta
=tan(90-2theta)=tan 4theta
=2 theta+4theta=90
6theta=90
theta=15
Now,
Sin 3Theta=sin 3*15=sin 45
So, sin 3 theta=1/2
=tan(90-2theta)=tan 4theta
=2 theta+4theta=90
6theta=90
theta=15
Now,
Sin 3Theta=sin 3*15=sin 45
So, sin 3 theta=1/2
Aa2311:
Sin 45=1/2
I m so sorry.... Sin 45=1/root 2
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