Question

If cot 20° =P

Then tan 160°-tan110°/1+tan160°+tan110°

Answer 1

Answer:

(2p1−p2)

1+tan160otan110otan160o−tan110o

=tan(160o−110o)=tan50o=cot40o=tan40o1

=1−tan220o2tan20o1=2p1−p2

Answer 2

Step-by-step explanation:

Given tan20 = p.

tan 160 = tan (180 - 20) = - tan20 = -p.

tan 110 = tan (90+20) = -cot 20 = -1/p.

tan 60 = sqrt(3). We know this.

So (tan160 - tan110) / (1 + tan60× tan110)

= (-p +1/p)/(1+ sqrt3 × -1/p)

= (1-p^2)/(p - sqrt3)

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