If cot(θ-30°)=1 then θ=?
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Answered by
1
Answer:
Given tanθ=cot(30∘+θ)
⟹cot(90∘−θ)=cot(30∘+θ)
⟹90∘−θ=30∘+θ
⟹2θ=90∘−30∘
⟹θ=30∘
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Answered by
14
Answer:
Here is your answer.
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