Question

if cot=5\12 and teta is an acute angle then secteta+cosect eata=

Answer 1

Answer:

221/60

Step-by-step explanation:

cotQ = base / oerpendicular

therefore base = 5 , perpendicular = 12 and hypotenuse = 13

so

secQ + cosecQ = 13/5 + 13/12

Answer 2

Answer:

cot=b/p

let b=5x andp=12x

h^2=b^2+p^2

h= root over 25x+144x

h=root over 169x

h=13x

sectheta + cosectheta=h/b+h/p

=13x/5x+13x/12x

= 156+65/60

=221/60

ANSWER BY KARAN