Physics, asked by souravnaker9969, 6 days ago

If cot=7/24 then value of sec theta will be

Answers

Answered by tennetiraj86
10

Explanation:

Given :-

Cot θ = 7/24

To find :-

Find the value of Sec θ ?

Solution :-

Given that

Cot θ = 7/24

=> 1/Tan θ = 7/24

=> Tan θ = 24/7

On squaring both sides then

=> ( Tan θ)² = (24/7)²

=> Tan² θ = 576/49

On adding 1 both sides then

=> 1 + Tan² θ = 1+(576/49)

=> 1 + Tan² θ = (49+576)/49

=> 1+ Tan² θ = 625/49

We know that

Sec²θ - Tan²θ = 1

=> Sec² θ = 625/49

=> Sec θ = √(625/49)

=> Sec θ = 25/7

therefore, Sec θ = 25/7

Answer:-

The value of Sec θ for the given problem is 25/7

Used formulae:-

→ Cot θ = 1/Tan θ

→ Sec²θ - Tan²θ = 1

Answered by royalpulugujju
0

\bold{ANSWER≈}

Given :

Cot 8 = 7/24

To find :

Find the value of Sec 9 ?

Solution :

Given that

Cot 8 = 7/24

=> 1/Tan 0 = 7/24

=> Tan 0 = 24/7

On squaring both sides then

=> (Tan 0)² = (24/7)² => Tan² = 576/49

On adding 1 both sides then

=> 1+ Tan² = 1+(576/49) => 1 + Tan² = (49+576)/49

=> 1+ Tan² = 625/49

We know that

Sec²0 - Tan²0 = 1

=> Sec² 0 = 625/49

=> Sec 0 = √(625/49)

=> Sec 8= 25/7

therefore, Sec 9 = 25/7

Answer:

The value of Sec 0 for the given problem is 25/7

Used formulae:

→ Cot 0 = 1/Tan Ⓒ

Sec²0 - Tan²0 = 1

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