If cot=7/24 then value of sec theta will be
Answers
Explanation:
Given :-
Cot θ = 7/24
To find :-
Find the value of Sec θ ?
Solution :-
Given that
Cot θ = 7/24
=> 1/Tan θ = 7/24
=> Tan θ = 24/7
On squaring both sides then
=> ( Tan θ)² = (24/7)²
=> Tan² θ = 576/49
On adding 1 both sides then
=> 1 + Tan² θ = 1+(576/49)
=> 1 + Tan² θ = (49+576)/49
=> 1+ Tan² θ = 625/49
We know that
Sec²θ - Tan²θ = 1
=> Sec² θ = 625/49
=> Sec θ = √(625/49)
=> Sec θ = 25/7
therefore, Sec θ = 25/7
Answer:-
The value of Sec θ for the given problem is 25/7
Used formulae:-
→ Cot θ = 1/Tan θ
→ Sec²θ - Tan²θ = 1
Given :
Cot 8 = 7/24
To find :
Find the value of Sec 9 ?
Solution :
Given that
Cot 8 = 7/24
=> 1/Tan 0 = 7/24
=> Tan 0 = 24/7
On squaring both sides then
=> (Tan 0)² = (24/7)² => Tan² = 576/49
On adding 1 both sides then
=> 1+ Tan² = 1+(576/49) => 1 + Tan² = (49+576)/49
=> 1+ Tan² = 625/49
We know that
Sec²0 - Tan²0 = 1
=> Sec² 0 = 625/49
=> Sec 0 = √(625/49)
=> Sec 8= 25/7
therefore, Sec 9 = 25/7
Answer:
The value of Sec 0 for the given problem is 25/7
Used formulae:
→ Cot 0 = 1/Tan Ⓒ
Sec²0 - Tan²0 = 1