Question

If cot θ=7/8, evaluate

(1+sinθ)(1-sinθ)/(1+cosθ)(1-cosθ)

ii) cot²θ​

Answer 1

Answer:

Answer:

49/64.

Step-by-step explanation:

Given Cot θ = 7/8

Now ,

(1 + sin θ)(1 - sinθ)/( 1 - cos θ)(1 + cos θ)

= 1 - Sin²θ / 1 - Cos²θ (∵ (a + b) (a-b) = a² - b²)

= Cos² θ/Sin²θ ( ∵ Sin²θ + Cos²θ = 1)

= Cot²θ

= (7/8)²

= 49/64.

Answer 2

Explanation:

113-64/113

113-49/113

= 49/64

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