if cotθ=7/8,then(1+sinθ)(1-sinθ)/(1+cosθ)(1-cosθ)
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Step-by-step explanation:
Given is cotθ=7/8 ⇒ opposite side = 8 and adjacent side=7 so, hypotenuse will be squareroot of sum of sqaures of 7 and 8 i.e sqrt7^2+8^2=√113 so now sinθ=8/√113 and cosθ=7/√113
(1+sinθ)(1-sinθ)/(1+cotθ)(1-cosθ)=1-sin^2θ/1+cotθ(1-cosθ)
= 1-64/113/1+7/8(1-7/√113)
on solving we get 49/(√113-7)√113
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