Question

If cot θ=78, evaluate: (1+ sinθ)(1- sinθ)/(1+ cosθ)(1- cos θ)

Answer 1

Answer:

cot θ=78

cot θ= hypotenuse / adjacent

        =78/1

consider a triangle abc right angled at b

∴ AB=1

    AC=78

BC=√$78^{2}$-$1^{2}$

     =√6083

sinθ=opposite/hypotenuse

      = BC/AB

       =√6083/78

cosθ=1/78

1+√6083 * 1-√6083 =  $1^{2} -\sqrt{6083} ^{2}$/$78^{2}$

       78            78      

=1-6083 /  1+  1    * 1- 1  

    6084       78         78

=1.64/1

=1.64

hope this will help you

pls mark brainliest