Question

if cot A = 1/2 secB = -5/3 where π<A<3π/2 and π/2<B<π. find the value of tan( A+B).​

Answer 1

Answer:

-2

Step-by-step explanation:

tan A=1/cot A=1/(1/2)= 2

tan B=√(sec^2B -1)= 4/3

tan (A+B)=( tan A +tan B) /(1-tan AtanB)

= -2

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