Question

If cot A= 1/√3 then find cosecA+ cosA/ secA- sinA

Answer 1

CotA = cot 60.
A= 60
Putting A=60 in the given equation.
=>Cosec 60 +cos 60 /sec 60 - sin 60


Then you can solve further

Answer 2

cot A = 1/√3 by using a right angle triangle mark the Ф on point A

= B/P

by using the pythagoras theoram

(H)² = (B)² + (P)²

(AC)² = (AB)² + (BC)²

AC² = (1)² + (√3)²

AC² = 1 + 3

AC² = 4

AC = √4

AC 2

COSEC A = H/P = 2/√3

COS A = B/H = 1/2

SEC A = H/B = 2/1

SIN A = P/H = √3/2

cosecФ + cosФ/secФ - sinФ

2/√3 + 1 /2/2 - √3/2

2/√3 + 1/4 - √3/2

8 + √3 - 6

___________

4√3

(2+√3 ) /4√3

Hope! it will be helpful for you