if cot A+1/cotA=2,prove that cot^2A+1/cot^2A=2
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Answered by
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Your answer
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Given that : - CotA + 1/CotA = 2
To prove : - Cot²A + 1/Cot²A = 2
Now,
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cotA + 1/cotA = 2
=> (cotA + 1/cotA)² = (2)². [Squaring both sides.]
=> cot²A + 2 × cotA × 1/cotA + 1/cot²A = 4
=> cot²A + 1/cot²A + 2 = 4
=> cot²A + 1/cot²A = 4 - 2
=> cot²A + 1/cot²A = 2
Hence, proved.
HOPE IT HELPS
----------------
Your answer
---------------------
Given that : - CotA + 1/CotA = 2
To prove : - Cot²A + 1/Cot²A = 2
Now,
--------
cotA + 1/cotA = 2
=> (cotA + 1/cotA)² = (2)². [Squaring both sides.]
=> cot²A + 2 × cotA × 1/cotA + 1/cot²A = 4
=> cot²A + 1/cot²A + 2 = 4
=> cot²A + 1/cot²A = 4 - 2
=> cot²A + 1/cot²A = 2
Hence, proved.
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