If cot A = 12/5. then find sin A , cosA and cosec A.
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4
Answer:
cotA= cosA/sinA
Therefore, cosA=12 and sinA=5
sinA=1/ cosecA
Therefore,cosecA=1/5
Step-by-step explanation:
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Given:- 12 cotA=5.
or, cot A=5/12.
or, cot²A=(5/12)²
or, cot²A=25/144
now cosec²A-cot²A=1.
or,cosec²A=1+cot²A
or,cosec²A=1+25/144
or,cosec²A=169/144
or,cosecA=13/12
so sinA=1/cosec A = 12/13
sin²A+cos²A=1
or,cos²A=1-sin²A
or,cos²A=1-(12/13)²
or,cos²A=1-144/169
or,cos²A=25/169
or,cosA=5/13
Thus Sin A=12/13.
Cos A=5/13
Cosec A=13/12.
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