Question

If cot A = 12/5. then find sin A , cosA and cosec A.

Answer 1

Given ,

Cot(A) = 12/5 = B/P

We know that ,

In right angled triangle ,

$\boxed{ \sf {(H)}^{2} = {(P)}^{2} + {(B)}^{2} }$

Thus ,

(H)² = (12)² + (5)²

(H)² = 144 + 25

(H)² = 169

H = √169

H = ±13

Since , the length can't be negative

Hence , The hypotenuse is 13 units

Therefore ,

• Sin(A) = P/H = 5/13
• Cos(A) = B/H = 12/13
• Cosec(A) = H/P = 13/5