If cot A = 12/5 , then the value of (sin A + cos A) x cosecA
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Ty our answer is...(17/5)
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Cot A = B/P i.e. B= 12, P=5
Then by pythagoras
H= 13
Sin A = P/H = 5/13
Cos A = B/H = 12/13
Cosec A = H/P = 13/5
Putting all the values
(5/13+12/13) x 13/5
17/13 x 13/5
17/5 IS THE ANSWER
IF satisfied then mark it as BRANLIEST
Then by pythagoras
H= 13
Sin A = P/H = 5/13
Cos A = B/H = 12/13
Cosec A = H/P = 13/5
Putting all the values
(5/13+12/13) x 13/5
17/13 x 13/5
17/5 IS THE ANSWER
IF satisfied then mark it as BRANLIEST
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