If Cot A = 5/7 then find the cosec A, tan A, Sec A.
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cot A = 5/7
☞ tan A = 1/cot A = 7/5.
☞ sec^2 A = 1 + tan^2 A.
(secA)^2 = 1 + (tanA)^2
(secA)^2 = 1 + (7/5)^2
(secA)^2 = 74/25
sec A = root74 ÷ 5 ____ is the ans.
☞ Similarly, cosec^A = 1 + cot^2A
So, put the value of cot A in above identity.
We get,
cosec A = root74 ÷ 7.......
Hope this will help you.......
Have u any doubt then ask me.
☛ ⛧⛧ Mr. Thakur ⛧⛧
☞ tan A = 1/cot A = 7/5.
☞ sec^2 A = 1 + tan^2 A.
(secA)^2 = 1 + (tanA)^2
(secA)^2 = 1 + (7/5)^2
(secA)^2 = 74/25
sec A = root74 ÷ 5 ____ is the ans.
☞ Similarly, cosec^A = 1 + cot^2A
So, put the value of cot A in above identity.
We get,
cosec A = root74 ÷ 7.......
Hope this will help you.......
Have u any doubt then ask me.
☛ ⛧⛧ Mr. Thakur ⛧⛧
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1
Bhai simple hh
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