Question

If cot A = 8/15 , find cos A

Answer 1

here you go ☆☆

given:-
cot A = 8/15

▪P = 15
▪B = 8
▪cos A = B/H

□to find =>
▪ H ▪ cos A

${h}^{2} = {b}^{2} + {p}^{2}$

${h}^{2} = {8}^{2} + {15}^{2}$

${h}^{2} = 64 + 225$

${h}^{2} = 289$

$h = \sqrt{289 } = > 17$

•so, cos A = 8/17

$\boxed{hope \: it \: helps}$

Answer 2

cotA=8/15
but we know cotA=adjacent/opposite
so,by using Pythagoras theorem
(8)^2+(15)^2=hyp^2
64+225=hyp^2
17=hyp
so,
cosA=8/17
I HOPE THIS WILL HELP U ☺☺☺☺☺☺✌✌✌✌✌✌✌✌