If cot a and cot B are the roots of the equation
x2-3x + 2 = 0, then what is cot (a + b) equal
to ?
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Answer:
cot(a +b) = 1/3
Step-by-step explanation:
Given cot α and cot β are the roots of x^2 -3x + 2 = 0
We know sum of the roots = - b/a and
product of the roots = c/a
So cot α + cot β = -(-3)/1 = 3 and
cot α. cot β = 2/1 = 2
We know that cot (α + β)
= (cotα cot β - 1)/ (cot α+ cotβ)
= (2–1)/ 3 = 1/3
So, cot (α + β) = 1/3.
Hope it helps u
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