Question

If cot (A+B)=0 in traingleABC, then find the value of cot C/2 ?

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Answer 1

Step-by-step explanation:

cot (A+B) = 0

=> cot (A+B) = cot 90

By comparing LHS and RHS, A+B=90

By angle sum property of triangle,

angle A + angle B + angle C = 180

=> 90 + angle C = 180

=> angle C = 180-90

=> angle C = 90

=> C/2 = 90/2

=> C/2 = 45

=> Cot C/2 = Cot 45

=> Cot C/2 = 1