If cot (A+B)=0 in traingleABC, then find the value of cot C/2 ?
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Step-by-step explanation:
cot (A+B) = 0
=> cot (A+B) = cot 90
By comparing LHS and RHS, A+B=90
By angle sum property of triangle,
angle A + angle B + angle C = 180
=> 90 + angle C = 180
=> angle C = 180-90
=> angle C = 90
=> C/2 = 90/2
=> C/2 = 45
=> Cot C/2 = Cot 45
=> Cot C/2 = 1
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