Question

If cot(A+B)=0, then sin(A+2B) is equal to: *

1 point

sin B

sin A

cos 2B

cos A

sin 2A

cos B

None

​

Answer 1

Answer:

 cosB

Step-by-step explanation:

Given cot(A+B)=0

=> cot(A+B) = cot90°

=> A+B = 90° --(1)

Now,

sin(A+2B)

= sin[(A+B)+B]

= sin(90°+B) /* From (1)*/

= cosB

Therefore,

Sin(A+2B) = cosB