Question

If Cot(A-B)=√3 and Tan(A+B)=√3; 0° < A+B ≤ 90°Then Find 'A' and 'B' *
A=30°and B=60°
A=15°and B=45°
A=45°and B=15°
A=60°and B=30°

Answer ASAP please

Answer 1

Answer:

hey good question

Step-by-step explanation:

if

A = 45 & B = 15

cot( 45-15)=cot30=√3

tan(45+15)=tan60=√3

so,.

A=45

B=15

hope this help u yar

mark my answer as brainliest

Answer 2

Step-by-step explanation:

Solution: tan (A + B) = √3 ⇒ tan (A + B) = tan 60° ⇒ (A + B) = 60° ... (i) tan (A – B) = 1/√3 ⇒ tan (A - B) = tan 30° ⇒ (A - B) = 30° ... (ii) Adding (i) and (ii), we get A + B + A - B = 60° + 30° 2A = 90° A= 45° Putting the value of A in equation (i) 45° + B = 60° ⇒ B = 60° - 45° ⇒ B = 15° Thus, A = 45° and B = 15° Read more on Sarthaks.com - https://www.sarthaks.com/2508/if-tan-a-b-3-and-tan-a-b-1-3-0-a-b-90-a-b-find-a-and-b