Question

if cot(A-B) =root3 and tan(A+B) = root 3 then find the value of secA

Answer 1

Cot(a-b)= root 3

Tan(a+b)= root 3

Cot (theta)=root 3 at theta=30

So,(a-b)=30....(1)

Tan(a+b)=root 3 at theta =60

So,(a+b)=60......(2)

Adding (1)&(2)

2a=90

So a=45

Sec(a)=sec(45)=root 2

Answer 2

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Cot(a-b)= root 3

Tan(a+b)= root 3

Cot (theta)=root 3 at theta=30

So,(a-b)=30.(1)

Tan(a+b)=root 3 at theta =60

So,(a+b)=60..(2)

Adding (1)&(2)

2a=90

So a=45

Sec(a)=sec(45)=root 2