if cot (a+d) equal to 1/√3 and tam 2a-b equal √3 find A and B
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Answer:
Step-by-step explanation:
cot θ = 1/√3
cot 60 = 1/√3
cot(a + b)=1/√3
a+b = 60
tan 2a-b = √3
tan 60 = √3
2a-b = 60
Now,
2a-b= 60 , a+b = 60
Solving equations now :
We get 3a = 120
a = 40
a+b = 60
b= 20
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