Math, asked by vijajkskumar488, 10 months ago

if cot (a+d) equal to 1/√3 and tam 2a-b equal √3 find A and B​

Answers

Answered by g7cool
1

Answer:

Step-by-step explanation:

cot θ =  1/√3

cot 60 = 1/√3

cot(a + b)=1/√3

a+b = 60

tan 2a-b = √3

tan 60 = √3

2a-b = 60

Now,

2a-b= 60 , a+b = 60

Solving equations now :

We get 3a = 120

a = 40

a+b = 60

b= 20

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