Question

If cot A = p/q then finds pcosa -qsina /pcosA+qsinA in trigonometry​

Answer 1

Step-by-step explanation:

1st angle = 38°

2nd angle = 52°

__________________________

\orange{\bigstar}★ Given \green{\bigstar}Given★ ★

1 . The measure of one angle is 12 degree more than half the measure of its compliment

★

Two angles

★

Let 1st angle be , " x "

So , Complementary angle be ,

" ( 90 - x ) "

From condition 1 ,

⇒ x = ( 90 - x ) / 2 + 12

⇒ 2x = 90- x + 24

⇒ 2x + x = 90 + 24

⇒ 3x = 114

⇒ x = 38 \pink{\bigstar}★ ★

So ,

1st angle , x = 38°

2nd angle , ( 90 - x ) = 52°