if cot b is equal to 12 by 5 find cos2 b
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Answered by
0
Answer:
cot B = base / perpendicular = 12 / 5
H² = P² + B²
H² = 25 + 144
H = √169
H = 13
HENCE ,
COSB = base / hypotenuse
cos B = 12 / 13
cos ² B = 144 / 169
Step-by-step explanation:
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Answered by
0
hey buddy here is your answer
As we know cot (A+B)=(cotB*cotA-1)/(cotB+cotA)
It is already given that cotB=12/5
cot2B=cot(B+B)
=>(cotB*cotB-1)/cotB+cotB
=>[(12/5)^2-1]/2(12/5)
=>[144/25]-1/24/5
=>119/120
hence cot2B=119/120
Hope it helps
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