Math, asked by AL3bd, 8 months ago

if cot b is equal to 12 by 5 find cos2 b

Answers

Answered by tanviiigrg
0

Answer:

cot B = base / perpendicular = 12 / 5

H² = P² + B²

H² = 25 + 144

H = √169

H = 13

HENCE ,

COSB = base / hypotenuse

cos B = 12 / 13

cos ² B = 144 / 169

Step-by-step explanation:

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Answered by Zaynroy
0

hey buddy here is your answer

As we know cot (A+B)=(cotB*cotA-1)/(cotB+cotA)

It is already given that cotB=12/5

   cot2B=cot(B+B)

=>(cotB*cotB-1)/cotB+cotB

=>[(12/5)^2-1]/2(12/5)

=>[144/25]-1/24/5

=>119/120

hence cot2B=119/120

Hope it helps

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