If cotΘ+cosΘ=x and cotΘ -cosΘ=y then x²-y²=
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Answer:
x² - y² = 4 (cot∅) ( cos∅ )
Step-by-step explanation:
{I have taken theta as ∅ , for typing purpose}
x²-y² = (x+y) (x-y)
=> { (cot∅ + cos∅) + ( cot∅ - cos∅ ) } × { ( (cot∅ + cos∅) - ( cot∅ - cos∅ ) }
=> (cot∅ + cos∅ + cot∅ - cos∅ ) × (cot∅ + cos∅ - cot∅ + cos∅ )
=> (2cot∅ ) (2cos∅)
=> x²-y² = 4 cot∅cos∅
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