Question

If cot
- cosec 0 = p, then cot 0 + cosec 0 = ?​

Answer 1

Answer:

-1/p

Step-by-step explanation:

cot^2(x)-cosec^2(x)=-1.

cot x- cosec x (cot x + cosec x)=- 1

So, cot x+ cosec x= -1/p. (Since p=cot x- cosec x)

Answer 2

${cosec}^{2} \theta - {cot}^{2} \theta = 1 \\ \\ (cosec \theta - cot \theta)(cosec \theta + cot \theta) = 1 \\ \\ p(cosec \theta + cot \theta) = 1 \\ \\ cosec \theta + cot \theta = \frac{1}{p}$