Question

If cot e
1; find the value of :
5 tan2 + 2 sin2 0 - 3​

Answer 1

tΘ=1

cotΘ=cot45

Θ=45

∘

5tan

2

Θ+2sin

2

Θ−3

= 5tan

2

45+2sin

2

45−3

= 5(1)

2

+2(

2

1

)

2

−3

= 5+1−3

Answer 2

cot = 1

cos / sin = 1/1

sin = 1

tan = 1/ cot = 1/1 = 1

now putting value in eq.

5tan {}^{2} + 2sin {}^{2} - 35tan

2

+2sin

2

−3

5(1) {}^{2} + 2(1) {}^{2} - 35(1)

2

+2(1)

2

−3

7 - 3 = 4