If cot Q =1 , find the value of 5 Tan^2 Q + 2sin^2 Q = 3
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Answer:
cotΘ=1
cotΘ=cot45
Θ=45∘
5tan2Θ+2sin2Θ−3
= 5tan245+2sin245−3
= 5(1)2+2(21)2−3
= 5+1−3
= 3
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