Question

if cot teta= 7/8,find (1+cos teta) (1_ cos teta)/( sin teta +1 ) (sin teta _1​

Answer 1

Answer:

-64/49

Step-by-step explanation:

(1+cos@)(1-cos@)/(sin@+1)(sin@-1)

=(1-cos2@)/(sin2@-1)

=sin2@/-cos2@

=-1/cot2@

=-1/(7/8)2

=-64/49

Answer 2

Answer:

-64/49

Step-by-step explanation:

cot¢=7/8

tan¢=8/7

hypotenuse² = height²+base²

=8²+7²

=64+49

=113

hypotenuse=✓113

sin¢=8/✓113

cos¢=7/✓113

[(1+cos¢)(1-cos¢)]/[(sin¢+1)(sin¢-1)]

=[(1+7/✓113)(1-7/✓113)]/[(8/✓113)/(8/✓113-1)]

=[1²-(7/✓113)²]/[-(1²-(8/✓113)²)]

=(1-49/113)/[-(1-64/113)]

=[(113-49)/113]/[-(113-64)/113]

=(64/113)/(-49/113)

=-64/49