Question

If cot theta=1/√3 then find the value of sin 3 theta

Answer 1

Answer:

let theta=,@

cot@=1/√3

@=60°

3sin@=3sin60°

3×√3/2

3√3/2

Answer 2

Answer: $Sin3\theta =0$

Step-by-step explanation:

Given: $Cot\theta =1/\sqrt{3}$

To find: $Sin3\theta$

$Cot\theta =1/\sqrt{3}=base/perpendicular\\hypotenuse=\sqrt{}\sqrt{3}^{2}+1^{2}=2\\Sin\theta =\sqrt{3}/2,Cos\theta =1/2\\\theta =60^{0}\\\\Putting\ the\ value\ of theta:\\Sin3\theta =Sin3\times 60^{0}=Sin 180^{0}=0$