If cot theta =1/under root 3
show that sin squar theta/1+ cos squat theta =3/5
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question
if cot∅=1/√3 ...
then prove that..
sin²∅/(1+cos²∅)=3/5
solution
cot∅=1/√3
=>cos∅=sin∅/√3
=>cos²∅=sin²∅/3
L.H.S=sin²∅/(1+cos²∅)
=sin²∅/(sin²∅+cos²∅+cos²∅)
=sin²∅/(sin²∅+2 cos²∅)
=sin²∅/(sin²∅+2sin²∅/3)
=sin²∅/sin²∅(1+2/3)
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